How to solve x + 4 > 5 c) x-

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve x + 4 > 5 c) x- | Equatix

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$$x + 4 \gt 5 \quad x$$

$x<1$

Subtract $5x$ from both sides.

$$x+4-5x>0$$

Combine $x$ and $-5x$ to get $-4x$.

$$-4x+4>0$$

Subtract $4$ from both sides. Anything subtracted from zero gives its negation.

$$-4x>-4$$

Divide both sides by $-4$. Since $-4$ is negative, the inequality direction is changed.

$$x<\frac{-4}{-4}$$

Divide $-4$ by $-4$ to get $1$.

$$x<1$$