How to solve x+5 <= 8x+9

Q: How to solve x+5 <= 8x+9

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve x+5 <= 8x+9 | Equatix

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3(r+2s)=2t-4

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Question

$$x+5 \leq 8x+9$$

Solve for x

$x\geq -\frac{4}{7}$

Solution Steps

Subtract $8x$ from both sides.

$$x+5-8x\leq 9$$

Combine $x$ and $-8x$ to get $-7x$.

$$-7x+5\leq 9$$

Subtract $5$ from both sides.

$$-7x\leq 9-5$$

Subtract $5$ from $9$ to get $4$.

$$-7x\leq 4$$

Divide both sides by $-7$. Since $-7$ is negative, the inequality direction is changed.

$$x\geq -\frac{4}{7}$$

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Solve for x

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