Solve x + 7 * (- 8/3) * x = 17/6 * (- 5x)/2 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$x+7\frac{-8}{3}x=\frac{17}{6}\frac{-5x}{2}$$

Solve for x

$x=0$

Steps for Solving Linear Equation

Multiply both sides of the equation by $6$, the least common multiple of $3,6,2$.

$$6x+14\left(-8\right)x=\frac{17}{2}\left(-5\right)x$$

Multiply $14$ and $-8$ to get $-112$.

$$6x-112x=\frac{17}{2}\left(-5\right)x$$

Combine $6x$ and $-112x$ to get $-106x$.

$$-106x=\frac{17}{2}\left(-5\right)x$$

Express $\frac{17}{2}\left(-5\right)$ as a single fraction.

$$-106x=\frac{17\left(-5\right)}{2}x$$

Multiply $17$ and $-5$ to get $-85$.

$$-106x=\frac{-85}{2}x$$

Fraction $\frac{-85}{2}$ can be rewritten as $-\frac{85}{2}$ by extracting the negative sign.

$$-106x=-\frac{85}{2}x$$

Add $\frac{85}{2}x$ to both sides.

$$-106x+\frac{85}{2}x=0$$

Combine $-106x$ and $\frac{85}{2}x$ to get $-\frac{127}{2}x$.

$$-\frac{127}{2}x=0$$

Product of two numbers is equal to $0$ if at least one of them is $0$. Since $-\frac{127}{2}$ is not equal to $0$, $x$ must be equal to $0$.

$$x=0$$