How to solve x+9 > 8-4x

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve x+9 > 8-4x | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$x+9 > 8-4x$$

Solve for x

$x>-\frac{1}{5}$

Solution Steps

Add $4x$ to both sides.

$$x+9+4x>8$$

Combine $x$ and $4x$ to get $5x$.

$$5x+9>8$$

Subtract $9$ from both sides.

$$5x>8-9$$

Subtract $9$ from $8$ to get $-1$.

$$5x>-1$$

Divide both sides by $5$. Since $5$ is positive, the inequality direction remains the same.

$$x>-\frac{1}{5}$$

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Question

Solve for x

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