Question

$$x+Ay_{1=11}y_{1}=3; (2t-1)y+2z=5; 2x-Ay+z=5$$

Solve for x, y, z

$x=\frac{11A+9}{3\left(2A+1\right)}$
$y=\frac{7}{3\left(2A+1\right)}$
$z=-\frac{1-5A}{2A+1}$
$A\neq -\frac{1}{2}$