How to solve x+-7/9=-8

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve x+-7/9=-8 | Equatix

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$$x+-7/9=-8$$

$x = -\frac{65}{9} = -7\frac{2}{9} \approx -7.222222222$

Fraction $\frac{-7}{9}$ can be rewritten as $-\frac{7}{9}$ by extracting the negative sign.

$$x-\frac{7}{9}=-8$$

Add $\frac{7}{9}$ to both sides.

$$x=-8+\frac{7}{9}$$

Convert $-8$ to fraction $-\frac{72}{9}$.

$$x=-\frac{72}{9}+\frac{7}{9}$$

Since $-\frac{72}{9}$ and $\frac{7}{9}$ have the same denominator, add them by adding their numerators.

$$x=\frac{-72+7}{9}$$

Add $-72$ and $7$ to get $-65$.

$$x=-\frac{65}{9}$$