Question

$$x+\underline{4,}; x^{2}-4; x^{2}-x-6$$

Answer

$$x+4*e^2*IM*u*n^2*d*r*l,;x^2-4;x^2-x-6$$

Solution


Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[\begin{aligned}&x+u{n}^{2}d{e}^{2}rl\imath \times 4,\\&{x}^{2}-4\\&{x}^{2}-x-6\end{aligned}\]
Regroup terms.
\[\begin{aligned}&x+4{e}^{2}\imath u{n}^{2}drl,\\&{x}^{2}-4\\&{x}^{2}-x-6\end{aligned}\]