$x+y=10x-y\text{ and }10x-y=3$

$x=\frac{6}{11}\approx 0.545454545$
$y = \frac{27}{11} = 2\frac{5}{11} = 2.4545454545454546$

$y = \frac{27}{11} = 2\frac{5}{11} = 2.4545454545454546$
$x = \frac{6}{11} = 0.5454545454545454$