How to solve x + y = 3y; x = 4

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve x + y = 3y; x = 4 | Equatix

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3(r+2s)=2t-4

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a⋅(b-2)=3b

Question

$$x+y=3y; x=4$$

Solve for x, y

$x=4$
$y=2$

Solution Steps

Consider the first equation. Insert the known values of variables into the equation.

$$4+y=3y$$

Subtract $3y$ from both sides.

$$4+y-3y=0$$

Combine $y$ and $-3y$ to get $-2y$.

$$4-2y=0$$

Subtract $4$ from both sides. Anything subtracted from zero gives its negation.

$$-2y=-4$$

Divide both sides by $-2$.

$$y=\frac{-4}{-2}$$

Divide $-4$ by $-2$ to get $2$.

$$y=2$$

The system is now solved.

$$x=4$$ $$y=2$$

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Question

Solve for x, y

Solution Steps