Solve for \(x\) in \(x+y=7\).
Solve for \(x\).
\[x+y=7\]
Subtract \(y\) from both sides.
\[x=7-y\]
\[x=7-y\]
Substitute \(x=7-y\) into \(x+y=1\).
Start with the original equation.
\[x+y=1\]
Let \(x=7-y\).
\[7-y+y=1\]
Simplify.
\[7=1\]
\[7=1\]
Since \(7=1\) is not true, this is an inconsistent system.
