How to solve x ^ 2 = 825

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve x ^ 2 = 825 | Equatix

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Question

$$x^{2}=825$$

Solve for x

$x=5\sqrt{33}\approx 28.722813233$
$x=-5\sqrt{33}\approx -28.722813233$

Steps by Finding Square Root

Steps Using the Quadratic Formula

Steps by Finding Square Root

Take the square root of both sides of the equation.

$$x=5\sqrt{33}$$ $$x=-5\sqrt{33}$$

Steps Using the Quadratic Formula

Subtract $825$ from both sides.

$$x^{2}-825=0$$

This equation is in standard form: $ax^{2}+bx+c=0$. Substitute $1$ for $a$, $0$ for $b$, and $-825$ for $c$ in the quadratic formula, $\frac{-b±\sqrt{b^{2}-4ac}}{2a}$.

$$x=\frac{0±\sqrt{0^{2}-4\left(-825\right)}}{2}$$

Square $0$.

$$x=\frac{0±\sqrt{-4\left(-825\right)}}{2}$$

Multiply $-4$ times $-825$.

$$x=\frac{0±\sqrt{3300}}{2}$$

Take the square root of $3300$.

$$x=\frac{0±10\sqrt{33}}{2}$$

Now solve the equation $x=\frac{0±10\sqrt{33}}{2}$ when $±$ is plus.

$$x=5\sqrt{33}$$

Now solve the equation $x=\frac{0±10\sqrt{33}}{2}$ when $±$ is minus.

$$x=-5\sqrt{33}$$

The equation is now solved.

$$x=5\sqrt{33}$$ $$x=-5\sqrt{33}$$

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Example

Question

Solve for x

Steps by Finding Square Root

Steps Using the Quadratic Formula

Steps by Finding Square Root

Steps Using the Quadratic Formula