Remove parentheses.
\[{x}^{2}\times \frac{d}{d}xy+xy\times \frac{d}{d}xy={4}^{2}subjecttoy\]
Simplify \({4}^{2}\) to \(16\).
\[{x}^{2}\times \frac{d}{d}xy+xy\times \frac{d}{d}xy=16subjecttoy\]
Cancel \(d\).
\[{x}^{2}xy+xy\times \frac{d}{d}xy=16subjecttoy\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[{x}^{2+1}y+xy\times \frac{d}{d}xy=16subjecttoy\]
Simplify \(2+1\) to \(3\).
\[{x}^{3}y+xy\times \frac{d}{d}xy=16subjecttoy\]
Cancel \(d\).
\[{x}^{3}y+xyxy=16subjecttoy\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[{x}^{3}y+{x}^{2}{y}^{2}=16subjecttoy\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[{x}^{3}y+{x}^{2}{y}^{2}=16subjec{t}^{2}oy\]
Regroup terms.
\[{x}^{3}y+{x}^{2}{y}^{2}=16esubjc{t}^{2}oy\]
Factor out the common term \({x}^{2}y\).
\[{x}^{2}y(x+y)=16esubjc{t}^{2}oy\]
Cancel \(y\) on both sides.
\[{x}^{2}(x+y)=16esubjc{t}^{2}o\]
Divide both sides by \(16\).
\[\frac{{x}^{2}(x+y)}{16}=esubjc{t}^{2}o\]
Divide both sides by \(e\).
\[\frac{\frac{{x}^{2}(x+y)}{16}}{e}=subjc{t}^{2}o\]
Simplify \(\frac{\frac{{x}^{2}(x+y)}{16}}{e}\) to \(\frac{{x}^{2}(x+y)}{16e}\).
\[\frac{{x}^{2}(x+y)}{16e}=subjc{t}^{2}o\]
Divide both sides by \(u\).
\[\frac{\frac{{x}^{2}(x+y)}{16e}}{u}=sbjc{t}^{2}o\]
Simplify \(\frac{\frac{{x}^{2}(x+y)}{16e}}{u}\) to \(\frac{{x}^{2}(x+y)}{16eu}\).
\[\frac{{x}^{2}(x+y)}{16eu}=sbjc{t}^{2}o\]
Divide both sides by \(b\).
\[\frac{\frac{{x}^{2}(x+y)}{16eu}}{b}=sjc{t}^{2}o\]
Simplify \(\frac{\frac{{x}^{2}(x+y)}{16eu}}{b}\) to \(\frac{{x}^{2}(x+y)}{16eub}\).
\[\frac{{x}^{2}(x+y)}{16eub}=sjc{t}^{2}o\]
Divide both sides by \(j\).
\[\frac{\frac{{x}^{2}(x+y)}{16eub}}{j}=sc{t}^{2}o\]
Simplify \(\frac{\frac{{x}^{2}(x+y)}{16eub}}{j}\) to \(\frac{{x}^{2}(x+y)}{16eubj}\).
\[\frac{{x}^{2}(x+y)}{16eubj}=sc{t}^{2}o\]
Divide both sides by \(c\).
\[\frac{\frac{{x}^{2}(x+y)}{16eubj}}{c}=s{t}^{2}o\]
Simplify \(\frac{\frac{{x}^{2}(x+y)}{16eubj}}{c}\) to \(\frac{{x}^{2}(x+y)}{16eubjc}\).
\[\frac{{x}^{2}(x+y)}{16eubjc}=s{t}^{2}o\]
Divide both sides by \({t}^{2}\).
\[\frac{\frac{{x}^{2}(x+y)}{16eubjc}}{{t}^{2}}=so\]
Simplify \(\frac{\frac{{x}^{2}(x+y)}{16eubjc}}{{t}^{2}}\) to \(\frac{{x}^{2}(x+y)}{16eubjc{t}^{2}}\).
\[\frac{{x}^{2}(x+y)}{16eubjc{t}^{2}}=so\]
Divide both sides by \(o\).
\[\frac{\frac{{x}^{2}(x+y)}{16eubjc{t}^{2}}}{o}=s\]
Simplify \(\frac{\frac{{x}^{2}(x+y)}{16eubjc{t}^{2}}}{o}\) to \(\frac{{x}^{2}(x+y)}{16eubjc{t}^{2}o}\).
\[\frac{{x}^{2}(x+y)}{16eubjc{t}^{2}o}=s\]
Switch sides.
\[s=\frac{{x}^{2}(x+y)}{16eubjc{t}^{2}o}\]
s=(x^2*(x+y))/(16*e*u*b*j*c*t^2*o)
