Solve x ^ 2 - 10 + 16 = 0 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$x^{2}-10+16=0$$

Solve for x (complex solution)

$x=-\sqrt{6}i\approx -0-2.449489743i$
$x=\sqrt{6}i\approx 2.449489743i$

Steps by Finding Square Root

Steps Using the Quadratic Formula

Steps by Finding Square Root

Add $-10$ and $16$ to get $6$.

$$x^{2}+6=0$$

Subtract $6$ from both sides. Anything subtracted from zero gives its negation.

$$x^{2}=-6$$

The equation is now solved.

$$x=\sqrt{6}i$$ $$x=-\sqrt{6}i$$

Steps Using the Quadratic Formula

Add $-10$ and $16$ to get $6$.

$$x^{2}+6=0$$

This equation is in standard form: $ax^{2}+bx+c=0$. Substitute $1$ for $a$, $0$ for $b$, and $6$ for $c$ in the quadratic formula, $\frac{-b±\sqrt{b^{2}-4ac}}{2a}$.

$$x=\frac{0±\sqrt{0^{2}-4\times 6}}{2}$$

Square $0$.

$$x=\frac{0±\sqrt{-4\times 6}}{2}$$

Multiply $-4$ times $6$.

$$x=\frac{0±\sqrt{-24}}{2}$$

Take the square root of $-24$.

$$x=\frac{0±2\sqrt{6}i}{2}$$

Now solve the equation $x=\frac{0±2\sqrt{6}i}{2}$ when $±$ is plus.

$$x=\sqrt{6}i$$

Now solve the equation $x=\frac{0±2\sqrt{6}i}{2}$ when $±$ is minus.

$$x=-\sqrt{6}i$$

The equation is now solved.

$$x=\sqrt{6}i$$ $$x=-\sqrt{6}i$$