$$x^{2}-3x+2; (x^{2}-7x+4); =1$$
$x=\frac{7-\sqrt{37}}{2}\approx 0.458618735\text{, }y=13-2\sqrt{37}\approx 0.834474939$
$x=\frac{\sqrt{37}+7}{2}\approx 6.541381265\text{, }y=2\sqrt{37}+13\approx 25.165525061$
