$$x^{2}-3x+2; (x^{2}-7x+41); =1$$
$x=\frac{-\sqrt{111}i+7}{2}\approx 3.5-5.267826876i\text{, }y=-2\sqrt{111}i-24\approx -24-21.071307506i$
$x=\frac{7+\sqrt{111}i}{2}\approx 3.5+5.267826876i\text{, }y=-24+2\sqrt{111}i\approx -24+21.071307506i$
