$$x^{2}-6ax+9a^{2}-16b^{2}$$
$\left(-x+3a-4b\right)\left(4b+3a-x\right)$
$$\left(x-3a-4b\right)\left(x-3a+4b\right)$$
$$\left(x-4b-3a\right)\left(x-3a+4b\right)$$
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$\left(x-3a\right)^{2}-16b^{2}$
