Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[v{e}^{2}rtx-9\ge 0\]
Regroup terms.
\[{e}^{2}vrtx-9\ge 0\]
Add \(9\) to both sides.
\[{e}^{2}vrtx\ge 9\]
Divide both sides by \({e}^{2}\).
\[vrtx\ge \frac{9}{{e}^{2}}\]
Divide both sides by \(v\).
\[rtx\ge \frac{\frac{9}{{e}^{2}}}{v}\]
Simplify \(\frac{\frac{9}{{e}^{2}}}{v}\) to \(\frac{9}{{e}^{2}v}\).
\[rtx\ge \frac{9}{{e}^{2}v}\]
Divide both sides by \(r\).
\[tx\ge \frac{\frac{9}{{e}^{2}v}}{r}\]
Simplify \(\frac{\frac{9}{{e}^{2}v}}{r}\) to \(\frac{9}{{e}^{2}vr}\).
\[tx\ge \frac{9}{{e}^{2}vr}\]
Divide both sides by \(t\).
\[x\ge \frac{\frac{9}{{e}^{2}vr}}{t}\]
Simplify \(\frac{\frac{9}{{e}^{2}vr}}{t}\) to \(\frac{9}{{e}^{2}vrt}\).
\[x\ge \frac{9}{{e}^{2}vrt}\]
x>=9/(e^2*v*r*t)