How to solve x ^ 2 + 1 = 4

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve x ^ 2 + 1 = 4 | Equatix

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Question

$$x^{2}+1=4$$

Solve for x

$x=\sqrt{3}\approx 1.732050808$
$x=-\sqrt{3}\approx -1.732050808$

Steps by Finding Square Root

Steps Using the Quadratic Formula

Steps by Finding Square Root

Subtract $1$ from both sides.

$$x^{2}=4-1$$

Subtract $1$ from $4$ to get $3$.

$$x^{2}=3$$

Take the square root of both sides of the equation.

$$x=\sqrt{3}$$ $$x=-\sqrt{3}$$

Steps Using the Quadratic Formula

Subtract $4$ from both sides.

$$x^{2}+1-4=0$$

Subtract $4$ from $1$ to get $-3$.

$$x^{2}-3=0$$

This equation is in standard form: $ax^{2}+bx+c=0$. Substitute $1$ for $a$, $0$ for $b$, and $-3$ for $c$ in the quadratic formula, $\frac{-b±\sqrt{b^{2}-4ac}}{2a}$.

$$x=\frac{0±\sqrt{0^{2}-4\left(-3\right)}}{2}$$

Square $0$.

$$x=\frac{0±\sqrt{-4\left(-3\right)}}{2}$$

Multiply $-4$ times $-3$.

$$x=\frac{0±\sqrt{12}}{2}$$

Take the square root of $12$.

$$x=\frac{0±2\sqrt{3}}{2}$$

Now solve the equation $x=\frac{0±2\sqrt{3}}{2}$ when $±$ is plus.

$$x=\sqrt{3}$$

Now solve the equation $x=\frac{0±2\sqrt{3}}{2}$ when $±$ is minus.

$$x=-\sqrt{3}$$

The equation is now solved.

$$x=\sqrt{3}$$ $$x=-\sqrt{3}$$

Show Solution

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Example

Question

Solve for x

Steps by Finding Square Root

Steps Using the Quadratic Formula

Steps by Finding Square Root

Steps Using the Quadratic Formula