Solve x ^ 2 + 10 + 2 = 0 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$x^{2}+10+2=0$$

Solve for x (complex solution)

$x=-2\sqrt{3}i\approx -0-3.464101615i$
$x=2\sqrt{3}i\approx 3.464101615i$

Steps by Finding Square Root

Steps Using the Quadratic Formula

Steps by Finding Square Root

Add $10$ and $2$ to get $12$.

$$x^{2}+12=0$$

Subtract $12$ from both sides. Anything subtracted from zero gives its negation.

$$x^{2}=-12$$

The equation is now solved.

$$x=2\sqrt{3}i$$ $$x=-2\sqrt{3}i$$

Steps Using the Quadratic Formula

Add $10$ and $2$ to get $12$.

$$x^{2}+12=0$$

This equation is in standard form: $ax^{2}+bx+c=0$. Substitute $1$ for $a$, $0$ for $b$, and $12$ for $c$ in the quadratic formula, $\frac{-b±\sqrt{b^{2}-4ac}}{2a}$.

$$x=\frac{0±\sqrt{0^{2}-4\times 12}}{2}$$

Square $0$.

$$x=\frac{0±\sqrt{-4\times 12}}{2}$$

Multiply $-4$ times $12$.

$$x=\frac{0±\sqrt{-48}}{2}$$

Take the square root of $-48$.

$$x=\frac{0±4\sqrt{3}i}{2}$$

Now solve the equation $x=\frac{0±4\sqrt{3}i}{2}$ when $±$ is plus.

$$x=2\sqrt{3}i$$

Now solve the equation $x=\frac{0±4\sqrt{3}i}{2}$ when $±$ is minus.

$$x=-2\sqrt{3}i$$

The equation is now solved.

$$x=2\sqrt{3}i$$ $$x=-2\sqrt{3}i$$