Question

$$x^{2}+4n+7=0$$

Solve for n

$n=\frac{-x^{2}-7}{4}$

Show Solution

Solve for x (complex solution)

$x=-\sqrt{-4n-7}$
$x=\sqrt{-4n-7}$

Solve for x

$x=\sqrt{-4n-7}$
$x=-\sqrt{-4n-7}\text{, }n\leq -\frac{7}{4}$