$$x^{2}+4n+7=0$$
$n=\frac{-x^{2}-7}{4}$
$x=-\sqrt{-4n-7}$
$x=\sqrt{-4n-7}$
$x=\sqrt{-4n-7}$
$x=-\sqrt{-4n-7}\text{, }n\leq -\frac{7}{4}$