Solve x ^ 2 + 4x + 0; x = - 4 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$x^{2}+4x-0; x=-4$$

Solve for x, y

$y=0$

Solution Steps

Consider the second equation. Insert the known values of variables into the equation.

$$y=\left(-4\right)^{2}+4\left(-4\right)-0$$

Calculate $-4$ to the power of $2$ and get $16$.

$$y=16+4\left(-4\right)-0$$

Multiply $4$ and $-4$ to get $-16$.

$$y=16-16-0$$

Subtract $16$ from $16$ to get $0$.

$$y=0-0$$

Subtracting $0$ from itself leaves $0$.

$$y=0$$

The system is now solved.

$$x=-4$$ $$y=0$$