$$x^{2}+4x+4y^{2}-8y+4=0; (x^{2}+4x)+y(y^{2}+2y)=-4$$
$x=-2\text{, }y=0$
$x=-4\sqrt{2}-2\approx -7.656854249\text{, }y=-\sqrt{7}i+1\approx 1-2.645751311i$
$x=4\sqrt{2}-2\approx 3.656854249\text{, }y=-\sqrt{7}i+1\approx 1-2.645751311i$
$x=-4\sqrt{2}-2\approx -7.656854249\text{, }y=1+\sqrt{7}i\approx 1+2.645751311i$
$x=4\sqrt{2}-2\approx 3.656854249\text{, }y=1+\sqrt{7}i\approx 1+2.645751311i$
$x=-2$
$y=0$
