Question

$$x^{2}+\frac{1}{x^{2}}+12; (x+\frac{i}{x})+38$$

Answer

$$x^2+1/x^2+12;x+IM/x+38$$

Solution


Remove parentheses.
\[\begin{aligned}&{x}^{2}+\frac{1}{{x}^{2}}+12\\&x+\frac{\imath }{x}+38\end{aligned}\]