Question

$$x ^ { 2 } + k x + 4 = 0$$

Solve for k

$k=-x-\frac{4}{x}$
$x\neq 0$

Show Solution

Solve for x (complex solution)

$x=\frac{\sqrt{k^{2}-16}-k}{2}$
$x=\frac{-\sqrt{k^{2}-16}-k}{2}$

Solve for x

$x=\frac{\sqrt{k^{2}-16}-k}{2}$
$x=\frac{-\sqrt{k^{2}-16}-k}{2}\text{, }|k|\geq 4$