Example

3(r+2s)=2t-4
a⋅(b-2)=3b
3(r+2s)=2t-4
a⋅(b-2)=3b

Question

$$x^{2}+kx+9=0-$$

Answer

k=x-9/x

Solution


Subtract \({x}^{2}\) from both sides.
\[kx+9={x}^{2}\]
Subtract \(9\) from both sides.
\[kx={x}^{2}-9\]
Divide both sides by \(x\).
\[k=\frac{{x}^{2}-9}{x}\]
Simplify  \(\frac{{x}^{2}-9}{x}\)  to  \(x-\frac{9}{x}\).
\[k=x-\frac{9}{x}\]
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