$$x^{2}+x^{2}+xx+x+3+1$$
$3x^{2}+x+4$
$$x^{2}+x^{2}+x^{2}+x+3+1$$
$$2x^{2}+x^{2}+x+3+1$$
$$3x^{2}+x+3+1$$
$$3x^{2}+x+4$$
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$6x+1$
$$\frac{\mathrm{d}}{\mathrm{d}x}(x^{2}+x^{2}+x^{2}+x+3+1)$$
$$\frac{\mathrm{d}}{\mathrm{d}x}(2x^{2}+x^{2}+x+3+1)$$
$$\frac{\mathrm{d}}{\mathrm{d}x}(3x^{2}+x+3+1)$$
$$\frac{\mathrm{d}}{\mathrm{d}x}(3x^{2}+x+4)$$
$$2\times 3x^{2-1}+x^{1-1}$$
$$6x^{2-1}+x^{1-1}$$
$$6x^{1}+x^{1-1}$$
$$6x^{1}+x^{0}$$
$$6x+x^{0}$$
$$6x+1$$
