Example

3(r+2s)=2t-4
a⋅(b-2)=3b
3(r+2s)=2t-4
a⋅(b-2)=3b

Question

$$x^{2v}+y^{av}-6x+4=0$$

Answer

$$y=(-x^(2*v)+6*x-4)^(1/(a*v))$$

Solution


Subtract \({x}^{2v}\) from both sides.
\[{y}^{av}-6x+4=-{x}^{2v}\]
Add \(6x\) to both sides.
\[{y}^{av}+4=-{x}^{2v}+6x\]
Subtract \(4\) from both sides.
\[{y}^{av}=-{x}^{2v}+6x-4\]
Take the \((av)\)th root of both sides.
\[y=\sqrt[av]{-{x}^{2v}+6x-4}\]
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