Solve x ^ 3 - 6 ^ 2 + 3x + 10 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$x^{3}-6^{2}+3x+10$$

Evaluate

$x^{3}+3x-26$

Differentiate w.r.t. x

$3\left(x^{2}+1\right)$

Steps Using Derivative Rule for Sum

Calculate $6$ to the power of $2$ and get $36$.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x^{3}-36+3x+10)$$

Add $-36$ and $10$ to get $-26$.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x^{3}-26+3x)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is $0$. The derivative of $ax^{n}$ is $nax^{n-1}$.

$$3x^{3-1}+3x^{1-1}$$

Subtract $1$ from $3$.

$$3x^{2}+3x^{1-1}$$

Subtract $1$ from $1$.

$$3x^{2}+3x^{0}$$

For any term $t$ except $0$, $t^{0}=1$.

$$3x^{2}+3\times 1$$

For any term $t$, $t\times 1=t$ and $1t=t$.

$$3x^{2}+3$$