How to solve x ^ 3 - 4/x

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve x ^ 3 - 4/x | Equatix

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$$x^{3}-\frac{4}{x}$$

$x^{3}-\frac{4}{x}$

To add or subtract expressions, expand them to make their denominators the same. Multiply $x^{3}$ times $\frac{x}{x}$.

$$\frac{x^{3}x}{x}-\frac{4}{x}$$

Since $\frac{x^{3}x}{x}$ and $\frac{4}{x}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{x^{3}x-4}{x}$$

Do the multiplications in $x^{3}x-4$.

$$\frac{x^{4}-4}{x}$$

$\frac{\left(x^{2}-2\right)\left(x^{2}+2\right)}{x}$