$$x^{3}+4x+4\cdot x^{2}-4$$
$\left(x+2\right)\left(3x+2\right)$
$$3x^{3-1}+4x^{1-1}+2\times 4x^{2-1}$$
$$3x^{2}+4x^{1-1}+2\times 4x^{2-1}$$
$$3x^{2}+4x^{0}+2\times 4x^{2-1}$$
$$3x^{2}+4x^{0}+8x^{2-1}$$
$$3x^{2}+4x^{0}+8x^{1}$$
$$3x^{2}+4x^{0}+8x$$
$$3x^{2}+4\times 1+8x$$
$$3x^{2}+4+8x$$
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$x^{3}+4x^{2}+4x-4$
