$$x^{3}+p(x)^{2}+9x+b=0$$
$\left\{\begin{matrix}p=-\frac{x^{3}+9x+b}{x^{2}}\text{, }&x\neq 0\\p\in \mathrm{C}\text{, }&b=0\text{ and }x=0\end{matrix}\right.$
$\left\{\begin{matrix}p=-\frac{x^{3}+9x+b}{x^{2}}\text{, }&x\neq 0\\p\in \mathrm{R}\text{, }&x=0\text{ and }b=0\end{matrix}\right.$
$b=-x\left(x^{2}+px+9\right)$
