$$x^{3}+px^{2}+9x+5; 2(x)$$
$3x^{2}+2px+q$
$$3x^{3-1}+2px^{2-1}+qx^{1-1}$$
$$3x^{2}+2px^{2-1}+qx^{1-1}$$
$$3x^{2}+2px^{1}+qx^{1-1}$$
$$3x^{2}+2px^{1}+qx^{0}$$
$$3x^{2}+2px+qx^{0}$$
$$3x^{2}+2px+q\times 1$$
$$3x^{2}+2px+q$$
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$x^{3}+px^{2}+qx+5$