How to solve x ^ 4 + 1/(x ^ 2)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve x ^ 4 + 1/(x ^ 2) | Equatix

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$$x^{4}+\frac{1}{x^{2}}$$

$x^{4}+\frac{1}{x^{2}}$

To add or subtract expressions, expand them to make their denominators the same. Multiply $x^{4}$ times $\frac{x^{2}}{x^{2}}$.

$$\frac{x^{4}x^{2}}{x^{2}}+\frac{1}{x^{2}}$$

Since $\frac{x^{4}x^{2}}{x^{2}}$ and $\frac{1}{x^{2}}$ have the same denominator, add them by adding their numerators.

$$\frac{x^{4}x^{2}+1}{x^{2}}$$

Do the multiplications in $x^{4}x^{2}+1$.

$$\frac{x^{6}+1}{x^{2}}$$

$\frac{\left(x^{2}+1\right)\left(x^{4}-x^{2}+1\right)}{x^{2}}$