Solve x ^ 4 + x ^ 3 + 2x ^ 2 + 6x + 8 / x + 2 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$x^{4}+x^{3}+2x^{2}+6x+8\div x+2$$

Evaluate

$x^{4}+x^{3}+2x^{2}+6x+2+\frac{8}{x}$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply $x^{4}+x^{3}+2x^{2}+6x+2$ times $\frac{x}{x}$.

$$\frac{\left(x^{4}+x^{3}+2x^{2}+6x+2\right)x}{x}+\frac{8}{x}$$

Since $\frac{\left(x^{4}+x^{3}+2x^{2}+6x+2\right)x}{x}$ and $\frac{8}{x}$ have the same denominator, add them by adding their numerators.

$$\frac{\left(x^{4}+x^{3}+2x^{2}+6x+2\right)x+8}{x}$$

Do the multiplications in $\left(x^{4}+x^{3}+2x^{2}+6x+2\right)x+8$.

$$\frac{x^{5}+x^{4}+2x^{3}+6x^{2}+2x+8}{x}$$

Factor

$\frac{x^{5}+x^{4}+2x^{3}+6x^{2}+2x+8}{x}$