Question

$$x ^ { 5 } - x ^ { 4 } + x ^ { 3 } - x ^ { 2 } + x - 5 x = - 1$$

Answer

$$h=(x^4/5+(n*g*IM)/(5*x)-x^3/5+x^2/5-x/5+1/5)/(e*w*n)$$

Solution


Regroup terms.
\[{x}^{5}-{x}^{4}+{x}^{3}-{x}^{2}+x-5ewhnx=-1\times \imath ng\]
Simplify  \(1\times \imath ng\)  to  \(ng\imath \).
\[{x}^{5}-{x}^{4}+{x}^{3}-{x}^{2}+x-5ewhnx=-ng\imath \]
Factor out the common term \(x\).
\[x({x}^{4}-{x}^{3}+{x}^{2}-x+1-5ewhn)=-ng\imath \]
Divide both sides by \(x\).
\[{x}^{4}-{x}^{3}+{x}^{2}-x+1-5ewhn=-\frac{ng\imath }{x}\]
Subtract \({x}^{4}\) from both sides.
\[-{x}^{3}+{x}^{2}-x+1-5ewhn=-\frac{ng\imath }{x}-{x}^{4}\]
Regroup terms.
\[-{x}^{3}+{x}^{2}-x+1-5ewhn=-{x}^{4}-\frac{ng\imath }{x}\]
Add \({x}^{3}\) to both sides.
\[{x}^{2}-x+1-5ewhn=-{x}^{4}-\frac{ng\imath }{x}+{x}^{3}\]
Subtract \({x}^{2}\) from both sides.
\[-x+1-5ewhn=-{x}^{4}-\frac{ng\imath }{x}+{x}^{3}-{x}^{2}\]
Add \(x\) to both sides.
\[1-5ewhn=-{x}^{4}-\frac{ng\imath }{x}+{x}^{3}-{x}^{2}+x\]
Subtract \(1\) from both sides.
\[-5ewhn=-{x}^{4}-\frac{ng\imath }{x}+{x}^{3}-{x}^{2}+x-1\]
Divide both sides by \(-5\).
\[ewhn=-\frac{-{x}^{4}-\frac{ng\imath }{x}+{x}^{3}-{x}^{2}+x-1}{5}\]
Simplify  \(\frac{-{x}^{4}-\frac{ng\imath }{x}+{x}^{3}-{x}^{2}+x-1}{5}\)  to  \(-\frac{{x}^{4}}{5}-\frac{\frac{ng\imath }{x}}{5}+\frac{{x}^{3}}{5}-\frac{{x}^{2}}{5}+\frac{x}{5}-\frac{1}{5}\).
\[ewhn=-(-\frac{{x}^{4}}{5}-\frac{\frac{ng\imath }{x}}{5}+\frac{{x}^{3}}{5}-\frac{{x}^{2}}{5}+\frac{x}{5}-\frac{1}{5})\]
Simplify  \(\frac{\frac{ng\imath }{x}}{5}\)  to  \(\frac{ng\imath }{5x}\).
\[ewhn=-(-\frac{{x}^{4}}{5}-\frac{ng\imath }{5x}+\frac{{x}^{3}}{5}-\frac{{x}^{2}}{5}+\frac{x}{5}-\frac{1}{5})\]
Remove parentheses.
\[ewhn=\frac{{x}^{4}}{5}+\frac{ng\imath }{5x}-\frac{{x}^{3}}{5}+\frac{{x}^{2}}{5}-\frac{x}{5}+\frac{1}{5}\]
Divide both sides by \(e\).
\[whn=\frac{\frac{{x}^{4}}{5}+\frac{ng\imath }{5x}-\frac{{x}^{3}}{5}+\frac{{x}^{2}}{5}-\frac{x}{5}+\frac{1}{5}}{e}\]
Divide both sides by \(w\).
\[hn=\frac{\frac{\frac{{x}^{4}}{5}+\frac{ng\imath }{5x}-\frac{{x}^{3}}{5}+\frac{{x}^{2}}{5}-\frac{x}{5}+\frac{1}{5}}{e}}{w}\]
Simplify  \(\frac{\frac{\frac{{x}^{4}}{5}+\frac{ng\imath }{5x}-\frac{{x}^{3}}{5}+\frac{{x}^{2}}{5}-\frac{x}{5}+\frac{1}{5}}{e}}{w}\)  to  \(\frac{\frac{{x}^{4}}{5}+\frac{ng\imath }{5x}-\frac{{x}^{3}}{5}+\frac{{x}^{2}}{5}-\frac{x}{5}+\frac{1}{5}}{ew}\).
\[hn=\frac{\frac{{x}^{4}}{5}+\frac{ng\imath }{5x}-\frac{{x}^{3}}{5}+\frac{{x}^{2}}{5}-\frac{x}{5}+\frac{1}{5}}{ew}\]
Divide both sides by \(n\).
\[h=\frac{\frac{\frac{{x}^{4}}{5}+\frac{ng\imath }{5x}-\frac{{x}^{3}}{5}+\frac{{x}^{2}}{5}-\frac{x}{5}+\frac{1}{5}}{ew}}{n}\]
Simplify  \(\frac{\frac{\frac{{x}^{4}}{5}+\frac{ng\imath }{5x}-\frac{{x}^{3}}{5}+\frac{{x}^{2}}{5}-\frac{x}{5}+\frac{1}{5}}{ew}}{n}\)  to  \(\frac{\frac{{x}^{4}}{5}+\frac{ng\imath }{5x}-\frac{{x}^{3}}{5}+\frac{{x}^{2}}{5}-\frac{x}{5}+\frac{1}{5}}{ewn}\).
\[h=\frac{\frac{{x}^{4}}{5}+\frac{ng\imath }{5x}-\frac{{x}^{3}}{5}+\frac{{x}^{2}}{5}-\frac{x}{5}+\frac{1}{5}}{ewn}\]