Question

$$x _{ 2 } + \frac{ 1 }{ { x }^{ 2 } } \times - { x }^{ 2 } - \frac{ 1 }{ { x }^{ 2 } }$$

Answer

$$x_2-1-1/x^2$$

Solution


Simplify  \(\frac{1}{{x}^{2}}\times -{x}^{2}\)  to  \(\frac{-{x}^{2}}{{x}^{2}}\).
\[x_2+\frac{-{x}^{2}}{{x}^{2}}-\frac{1}{{x}^{2}}\]
Move the negative sign to the left.
\[x_2-1-\frac{1}{{x}^{2}}\]