Question

$$x \times ( y + x ) = x y + x x = 2 , y = \frac { 1 } { 3 } z = \frac { 1 } { 6 }$$

Evaluate (complex solution)

$x\left(x+y\right)=2,y=\frac{1}{6}\text{ and }z=\frac{1}{2}$

Solve for x

$x = \frac{4}{3} = 1\frac{1}{3} = 1.3333333333333333$
$x=-\frac{3}{2}\text{, }y=\frac{1}{6}\text{ and }z=\frac{1}{2}$

Solve for z

$z = \frac{1}{2} = 0.5$
$\left(x=-\frac{3}{2}\text{ or }x=\frac{4}{3}\right)\text{ and }y=\frac{1}{6}$