How to solve xx = 8.25

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve xx = 8.25 | Equatix

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Question

$$x\times x=8.25$$

Solve for x

$x = \frac{\sqrt{33}}{2} \approx 2.872281323$
$x = -\frac{\sqrt{33}}{2} \approx -2.872281323$

Steps by Finding Square Root

Steps Using the Quadratic Formula

Steps by Finding Square Root

Multiply $x$ and $x$ to get $x^{2}$.

$$x^{2}=8.25$$

Take the square root of both sides of the equation.

$$x=\frac{\sqrt{33}}{2}$$ $$x=-\frac{\sqrt{33}}{2}$$

Steps Using the Quadratic Formula

Multiply $x$ and $x$ to get $x^{2}$.

$$x^{2}=8.25$$

Subtract $8.25$ from both sides.

$$x^{2}-8.25=0$$

This equation is in standard form: $ax^{2}+bx+c=0$. Substitute $1$ for $a$, $0$ for $b$, and $-8.25$ for $c$ in the quadratic formula, $\frac{-b±\sqrt{b^{2}-4ac}}{2a}$.

$$x=\frac{0±\sqrt{0^{2}-4\left(-8.25\right)}}{2}$$

Square $0$.

$$x=\frac{0±\sqrt{-4\left(-8.25\right)}}{2}$$

Multiply $-4$ times $-8.25$.

$$x=\frac{0±\sqrt{33}}{2}$$

Now solve the equation $x=\frac{0±\sqrt{33}}{2}$ when $±$ is plus.

$$x=\frac{\sqrt{33}}{2}$$

Now solve the equation $x=\frac{0±\sqrt{33}}{2}$ when $±$ is minus.

$$x=-\frac{\sqrt{33}}{2}$$

The equation is now solved.

$$x=\frac{\sqrt{33}}{2}$$ $$x=-\frac{\sqrt{33}}{2}$$

Show Solution

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Example

Question

Solve for x

Steps by Finding Square Root

Steps Using the Quadratic Formula

Steps by Finding Square Root

Steps Using the Quadratic Formula