Question

$$x y , \frac { 2 - \sqrt { 5 } } { 2 + 3 \sqrt { 5 } } = x + y \sqrt { 5 }$$

Solve for x, y, z (complex solution)

$x=-\sqrt{5}y+\frac{8\sqrt{5}}{41}-\frac{19}{41}\text{, }y=\frac{\sqrt{-33620\sqrt{5}z+3405-1520\sqrt{5}}}{410}-\frac{19\sqrt{5}}{410}+\frac{4}{41}\text{, }z\in \mathrm{C}$
$x=-\sqrt{5}y+\frac{8\sqrt{5}}{41}-\frac{19}{41}\text{, }y=-\frac{\sqrt{-33620\sqrt{5}z+3405-1520\sqrt{5}}}{410}-\frac{19\sqrt{5}}{410}+\frac{4}{41}\text{, }z\in \mathrm{C}$

Solve for x, y, z

$x=-\sqrt{5}y+\frac{8\sqrt{5}}{41}-\frac{19}{41}\text{, }y=\frac{\sqrt{-33620\sqrt{5}z+3405-1520\sqrt{5}}}{410}-\frac{19\sqrt{5}}{410}+\frac{4}{41}\text{, }z\leq \frac{681\sqrt{5}}{33620}-\frac{76}{1681}$
$x=-\sqrt{5}y+\frac{8\sqrt{5}}{41}-\frac{19}{41}\text{, }y=-\frac{\sqrt{-33620\sqrt{5}z+3405-1520\sqrt{5}}}{410}-\frac{19\sqrt{5}}{410}+\frac{4}{41}\text{, }z\leq \frac{681\sqrt{5}}{33620}-\frac{76}{1681}$