How to solve x2-6 imes-16

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve x2-6\times-16 | Equatix

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Question

$$x2-6 \times -16$$

Evaluate

$x_{2}+96$

Show Solution

Differentiate w.r.t. x_2

$1$

Steps Using Derivative Rule for Sum

Multiply $6$ and $-16$ to get $-96$.

$$\frac{\mathrm{d}}{\mathrm{d}x_{2}}(x_{2}-\left(-96\right))$$

The opposite of $-96$ is $96$.

$$\frac{\mathrm{d}}{\mathrm{d}x_{2}}(x_{2}+96)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is $0$. The derivative of $ax^{n}$ is $nax^{n-1}$.

$$x_{2}^{1-1}$$

Subtract $1$ from $1$.

$$x_{2}^{0}$$

For any term $t$ except $0$, $t^{0}=1$.

$$1$$

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Example

Question

Evaluate

Solution Steps

Differentiate w.r.t. x_2

Steps Using Derivative Rule for Sum