$$x2+2x-8=0$$
$x=-\frac{x_{2}}{2}+4$
$$2x-8=-x_{2}$$
$$2x=-x_{2}+8$$
$$2x=8-x_{2}$$
$$\frac{2x}{2}=\frac{8-x_{2}}{2}$$
$$x=\frac{8-x_{2}}{2}$$
$$x=-\frac{x_{2}}{2}+4$$
Show Solution
Hide Solution
$x_{2}=8-2x$
$$x_{2}-8=-2x$$
$$x_{2}=-2x+8$$