$$x2+2x+3y=6$$
$x=-\frac{x_{2}}{2}-\frac{3y}{2}+3$
$$2x+3y=6-x_{2}$$
$$2x=6-x_{2}-3y$$
$$2x=6-3y-x_{2}$$
$$\frac{2x}{2}=\frac{6-3y-x_{2}}{2}$$
$$x=\frac{6-3y-x_{2}}{2}$$
$$x=-\frac{x_{2}}{2}-\frac{3y}{2}+3$$
Show Solution
Hide Solution
$x_{2}=6-3y-2x$
$$x_{2}+3y=6-2x$$
$$x_{2}=6-2x-3y$$