$$x2+y2-16x-4y+32=0$$
$x=\frac{x_{2}-4y+y_{2}+32}{16}$
$$y_{2}-16x-4y+32=-x_{2}$$
$$-16x-4y+32=-x_{2}-y_{2}$$
$$-16x+32=-x_{2}-y_{2}+4y$$
$$-16x=-x_{2}-y_{2}+4y-32$$
$$-16x=-x_{2}+4y-y_{2}-32$$
$$\frac{-16x}{-16}=\frac{-x_{2}+4y-y_{2}-32}{-16}$$
$$x=\frac{-x_{2}+4y-y_{2}-32}{-16}$$
$$x=\frac{x_{2}}{16}+\frac{y_{2}}{16}-\frac{y}{4}+2$$
Show Solution
Hide Solution
$x_{2}=-\left(32+y_{2}-4y-16x\right)$
$$x_{2}-16x-4y+32=-y_{2}$$
$$x_{2}-4y+32=-y_{2}+16x$$
$$x_{2}+32=-y_{2}+16x+4y$$
$$x_{2}=-y_{2}+16x+4y-32$$