Question

$$xx^{2}+6x\ge1-5$$

Answer

x>=-0.6258171081543

Solution


Simplify  \(x{x}^{2}\)  to  \({x}^{3}\).
\[{x}^{3}+6x\ge 1-5\]
Simplify  \(1-5\)  to  \(-4\).
\[{x}^{3}+6x\ge -4\]
Move all terms to one side.
\[{x}^{3}+6x+4\ge 0\]
No root was found algebraically. However, the following root(s) were found by numerical methods.
\[x\ge -0.625817\]