Question

$$y = 2 ^ { \frac { 1 } { \log x ^ { 8 } } } d x =$$

Solve for d (complex solution)

$d=\frac{y}{x\times 2^{\log_{x^{8}}\left(10\right)}}$
$x\neq 1\text{ and }x\neq -1\text{ and }x\neq -i\text{ and }x\neq i\text{ and }x\neq \sqrt{2}\left(\frac{1}{2}-\frac{1}{2}i\right)\text{ and }x\neq \sqrt{2}\left(-\frac{1}{2}-\frac{1}{2}i\right)\text{ and }x\neq \sqrt{2}\left(-\frac{1}{2}+\frac{1}{2}i\right)\text{ and }x\neq \sqrt{2}\left(\frac{1}{2}+\frac{1}{2}i\right)\text{ and }x\neq 0$

Solve for d

$d=\frac{y\times 2^{-\frac{\log_{x^{2}}\left(10\right)}{4}}}{x}$
$x\neq 0\text{ and }|x|\neq 1$