$$y=2x^{2}-8x+3$$
$x=\frac{\sqrt{2y+10}}{2}+2$
$x=-\frac{\sqrt{2y+10}}{2}+2$
$x=\frac{\sqrt{2y+10}}{2}+2$
$x=-\frac{\sqrt{2y+10}}{2}+2\text{, }y\geq -5$
$y=2x^{2}-8x+3$