$$y=6x^{2}-8x+1$$
$x=\frac{\sqrt{6y+10}}{6}+\frac{2}{3}$
$x=-\frac{\sqrt{6y+10}}{6}+\frac{2}{3}$
$x=\frac{\sqrt{6y+10}}{6}+\frac{2}{3}$
$x=-\frac{\sqrt{6y+10}}{6}+\frac{2}{3}\text{, }y\geq -\frac{5}{3}$
$y=6x^{2}-8x+1$