$x=\frac{\sqrt{32y+89}-5}{16}$
$x=\frac{-\sqrt{32y+89}-5}{16}$

$x=\frac{\sqrt{32y+89}-5}{16}$
$x=\frac{-\sqrt{32y+89}-5}{16}\text{, }y\geq -\frac{89}{32}$

$y=8x^{2}+5x-2$