$$y= { x }^{ 2 } +x-6$$
$x=\frac{\sqrt{4y+25}-1}{2}$
$x=\frac{-\sqrt{4y+25}-1}{2}$
$x=\frac{\sqrt{4y+25}-1}{2}$
$x=\frac{-\sqrt{4y+25}-1}{2}\text{, }y\geq -\frac{25}{4}$
$y=\left(x-2\right)\left(x+3\right)$