How to solve y=(1)/(3)x-3

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve y=(1)/(3)x-3 | Equatix

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$$y= \frac{ 1 }{ 3 } x-3$$

$x=3\left(y+3\right)$

Swap sides so that all variable terms are on the left hand side.

$$\frac{1}{3}x-3=y$$

Add $3$ to both sides.

$$\frac{1}{3}x=y+3$$

Multiply both sides by $3$.

$$\frac{\frac{1}{3}x}{\frac{1}{3}}=\frac{y+3}{\frac{1}{3}}$$

Dividing by $\frac{1}{3}$ undoes the multiplication by $\frac{1}{3}$.

$$x=\frac{y+3}{\frac{1}{3}}$$

Divide $y+3$ by $\frac{1}{3}$ by multiplying $y+3$ by the reciprocal of $\frac{1}{3}$.

$$x=3y+9$$

$y=\frac{x-9}{3}$